newbee and xpath

Dev Community Dev/API Corner
1

Okay, I'm brand new to this, so please help me out here.

 

What I'm trying to do, is to get the file path of all sections defined within PMS

 

 

sections = XML.ElementFromURL(":32400/library/sections/.xpath('//Directory')    
        for section in sections:

title = section.get('title')

 

 

And I got titles of the sections, but....

 

How do I get the path of each section?

 

Best Regards

 

Tommy

2

There could be more than one path for a given section. But you want something along the lines of:

for section in sections:
    title = section.get('title')
    paths = section.xpath('Location/@path')
    print "%s - %s" % (title, ', '.join(paths))
3

There could be more than one path for a given section. But you want something along the lines of:

for section in sections:
    title = section.get('title')
    paths = section.xpath('Location/@path')
    print "%s - %s" % (title, ', '.join(paths))

Sir...You have just saved my marriage, cuz. I was close to go crazy here.....

I'll take this suggestion out for a spin, but regardless, huge thanx for responding here.....

You got one + point in my white book for this, so feel free to cash in @ any time

Best regards

Tommy

4

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